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AS Problem Collection

w2311x21
12x22
1323
w2211x21
12x22
13x23
w2111x21
12x22
1323

9701_w22_qp_12

18

Wrong AnsC
Correct AnsD
ExplainThe strength of metal bonds is decided by the number of delocalized electrons

9701_w21_qp_12

11

Wrong AnsB
Correct AnsD
ExplainBoth are catalysts

16

Wrong AnsD
Correct AnsC
ExplainAgClAgCl dissolves in ammonia to form [Ag(NH3)2]+[Ag(NH_3)_2]^+; AgIAgI does not solve in ammonia

26

Wrong AnsB
Correct AnsD
ExplainAlcohol's corresponding carboxylic acid has stronger H-bond than itself. Aldehydes and ketones do not have H-bonds.

29

Wrong AnsA
Correct AnsB
ExplainMgCO3MgCO3 only react with COOH-COOH

31

Wrong Ans1, 2
Correct Ans1, 2, 3
ExplainThe total area represents the total number of particles

9701_w23_qp_11

5

Wrong AnsC
Correct AnsA
ExplainAs solid, AlCl3AlCl3 forms giant lattice. As liquid and vapor (< 400℃), it forms Al2Cl6Al2Cl6 dimer. As vapor (> 400℃), it forms AlCl3AlCl3 monomer.

16

Wrong AnsB
Correct AnsA
ExplainAlCl3+3H2OAl(OH)3+3HClAlCl_3 + 3H_2O \rightarrow Al(OH)_3 + 3HCl

Extra:

SiCl4+2H2O2SiO2+4HClSiCl_4 + 2H_2O \rightarrow 2SiO_2 + 4HCl

SiCl4+4H2OH4SiO4+4HClSiCl_4 + 4H_2O \rightarrow H_4SiO_4 + 4HCl

9701_w22_qp_11

Ground state: lowest possible energy state

2NaBr+2H2​SO4​→Br2​+SO2​+Na2​SO4​+2H2​O

29

Wrong AnsA
Correct AnsD
ExplainH2SO4H_2SO_4 opens COO-COO- of the bottom right ring; KMnO4KMnO_4 add OH to each end of C=CC=C. KMnO4KMnO_4 does not provide O so alcohol is not oxidized to aldehyde or ketone, but K2Cr2O7K_2Cr_2O_7 can

32

Wrong AnsB
Correct AnsA
ExplainSaturated hexane ring is not planar but twisted. Benzane ring is planar.

9701_w21_qp_11

8

Wrong AnsA
Correct AnsC
ExplainEnthalpy change is analyzed under room condition (298 K + 100kPa)

19

Wrong AnsD
Correct AnsB
ExplainDoes not directly linked to the formation photochemical smog. Though, NOxNO_x + Volatile Organic Compounds sunlight\xrightarrow{\text{sunlight}} photochemical smog.

26

Wrong AnsC
Correct AnsD
ExplainThe intermediate is R2C(O)CNR_2C(O^-)CN, with no OH-OH.

9701_w23_qp_12

17

Wrong AnsX
Correct Ans2, 3
ExplainFor 2 and 3, though the equilibrium moves to the left/does not move, the concentration increases, so the rate of change of the forward reaction increases.

33

Wrong AnsB
Correct AnsA
ExplainNaOH(ethanol) can only be used in dehydrohalogenation, removing HX. To dehydrate, use conc. H₂SO₄.